in addition with charts i am interested in knowing that how companies do these surveys and on what basis.
I need charts on customer satisfaction from different companies.?
Please check some prominant suevey companies...!Pinecone research, Surveysavvy, Greenfieldonline are some of the larger survey companies, who pay regularly . A list of companies you can join for free , with details of amounts you will receive as payment, is available at http://tinyurl.com/mx9ga
Monday, May 24, 2010
Anybody help me to survey Pneumatic Conveying System?
i supplied Pneumatic Conveying System in some of the cement companies in india , now i want to grow up my bussiness , how to findout my Customers in wright Place
Anybody help me to survey Pneumatic Conveying System?
The Food Corporation of India used to deploy pneumatic conveyors for handling bulk food grain. The Engg. Divn. of FCI may be able to give more information on this. May contact FCI office in Delhi %26amp; Bombay.
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Anybody help me to survey Pneumatic Conveying System?
The Food Corporation of India used to deploy pneumatic conveyors for handling bulk food grain. The Engg. Divn. of FCI may be able to give more information on this. May contact FCI office in Delhi %26amp; Bombay.
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Which stat is more impressive?...93% would refer or the 'A' average?
Our company survey all active customers (close to 50,000). There are two stats that we are considering using.
1- 93% of our customers would refer us to a friend.
2- Our customers rated our service with an 'A'
Which do you think would be more effective in advertising?
Which stat is more impressive?...93% would refer or the 'A' average?
Yes I believe so !!!
Reply:if the 93% is a true number and not just ballooned in order to show progress , and or work relativity , than i'd say advertising is in the bag as word of mouth , as any American knows , is the best ad a place can have . though it doesnt hurt to shoot for the remaining 7% by putting it out on the waves .
Reply:I think the first one is more impressive. alot of times I think people rate A meaning 'no complaints' but that doesn't mean they loved it either.
Reply:93% because it makes it seem like you guys actually bothered to survey a bunch of people
A makes it sound like you didnt bother to figure out the %age
Reply:93% because it shows how hard you guys worked to come up with it
1- 93% of our customers would refer us to a friend.
2- Our customers rated our service with an 'A'
Which do you think would be more effective in advertising?
Which stat is more impressive?...93% would refer or the 'A' average?
Yes I believe so !!!
Reply:if the 93% is a true number and not just ballooned in order to show progress , and or work relativity , than i'd say advertising is in the bag as word of mouth , as any American knows , is the best ad a place can have . though it doesnt hurt to shoot for the remaining 7% by putting it out on the waves .
Reply:I think the first one is more impressive. alot of times I think people rate A meaning 'no complaints' but that doesn't mean they loved it either.
Reply:93% because it makes it seem like you guys actually bothered to survey a bunch of people
A makes it sound like you didnt bother to figure out the %age
Reply:93% because it shows how hard you guys worked to come up with it
Legitimate work from home, I live in Asia?
like customer service.....etc
no scam,mlm, paid surveys, please
i was scammed once over paid surveys
Legitimate work from home, I live in Asia?
right you are!
Reply:maybe you can start a mini food business...
Reply:Try this website:-http://www.seekluck.com/
Reply:If you want to work from your computer at home, you are probably going to have to do it as a business owner, rather than as an employee. There are no online work-at-home "jobs".
When you apply for a job offline, in the bricks and mortar world, do you have to pay anything? Of course not. It should be the same in the online world. If you are asked to pay any money, at best, it is a business opportunity, but more likely it is just a scam.
Be very careful that you don't get scammed.
I do affiliate marketing online. I've been doing it for a year and I'm getting ready to quit my regular job, as I am now making over $10k per month. However, it takes dedicated, persistent work, at least a few thousand of initial working capital, decent organizational skills, and a healthy dose of motivation, but you can make a living at it if you stick with it.
But that is a business.
Starting a business requires a lot of work and dedication. You cannot start a business this week and expect to be earning a good profit next week.
Employees tend to have a "job" mindset whereby they worked this week, so they expect to see results this week (i.e. a paycheck this week).
In business, you don't see results like that. Take, for instance, starting a new restaurant. You'll first have to choose a location. The most successful restaurants have their own location, with their own parking lots.
If you wanted to open a restaurant like that, you'd spend a couple of months looking for the right location. Then you'd spend thousands of dollars for an architect to help design the plans with you. Then you'd spend thousands of dollars getting your plans approved by the local authorities.
And then, after all that, you'd be approved to spend hundreds of thousands of dollars on hiring a firm to actually build your building. And after that, you'd spend tens of thousands of dollars to install the interior decorations.
And then you'd spend thousands of dollars hiring employees and training them, as well as having them prepare for the grand opening.
And then, after over a year and spending over a half million dollars, you'd be ready to open the doors and start earning your first dollar.
I say this to illustrate my point: businesses take time and money up front to develop. In the longer period of time, this time and money invested up front will pay off.
But businesses take time to develop!
It is not like being an employee where you get instant results, meaning work this week, get paid this week.
Business is not like that.
If you want something easy, with no investment, you could probably make $500 to $1000 per month getting paid by companies to write postings on blogs about their products. That's about the only legitimate way that I know of to earn money online without any investment.
I wish you much business success, if you choose to go that route.
Reply:Perhaps, you can work from home.
I heard about this a lots but I never found.
If you find such work, pls contact me
%26lt;msuddin2008@yahoo.com%26gt;
no scam,mlm, paid surveys, please
i was scammed once over paid surveys
Legitimate work from home, I live in Asia?
right you are!
Reply:maybe you can start a mini food business...
Reply:Try this website:-http://www.seekluck.com/
Reply:If you want to work from your computer at home, you are probably going to have to do it as a business owner, rather than as an employee. There are no online work-at-home "jobs".
When you apply for a job offline, in the bricks and mortar world, do you have to pay anything? Of course not. It should be the same in the online world. If you are asked to pay any money, at best, it is a business opportunity, but more likely it is just a scam.
Be very careful that you don't get scammed.
I do affiliate marketing online. I've been doing it for a year and I'm getting ready to quit my regular job, as I am now making over $10k per month. However, it takes dedicated, persistent work, at least a few thousand of initial working capital, decent organizational skills, and a healthy dose of motivation, but you can make a living at it if you stick with it.
But that is a business.
Starting a business requires a lot of work and dedication. You cannot start a business this week and expect to be earning a good profit next week.
Employees tend to have a "job" mindset whereby they worked this week, so they expect to see results this week (i.e. a paycheck this week).
In business, you don't see results like that. Take, for instance, starting a new restaurant. You'll first have to choose a location. The most successful restaurants have their own location, with their own parking lots.
If you wanted to open a restaurant like that, you'd spend a couple of months looking for the right location. Then you'd spend thousands of dollars for an architect to help design the plans with you. Then you'd spend thousands of dollars getting your plans approved by the local authorities.
And then, after all that, you'd be approved to spend hundreds of thousands of dollars on hiring a firm to actually build your building. And after that, you'd spend tens of thousands of dollars to install the interior decorations.
And then you'd spend thousands of dollars hiring employees and training them, as well as having them prepare for the grand opening.
And then, after over a year and spending over a half million dollars, you'd be ready to open the doors and start earning your first dollar.
I say this to illustrate my point: businesses take time and money up front to develop. In the longer period of time, this time and money invested up front will pay off.
But businesses take time to develop!
It is not like being an employee where you get instant results, meaning work this week, get paid this week.
Business is not like that.
If you want something easy, with no investment, you could probably make $500 to $1000 per month getting paid by companies to write postings on blogs about their products. That's about the only legitimate way that I know of to earn money online without any investment.
I wish you much business success, if you choose to go that route.
Reply:Perhaps, you can work from home.
I heard about this a lots but I never found.
If you find such work, pls contact me
%26lt;msuddin2008@yahoo.com%26gt;
Math QUestion?
The utility company wishes to estimate the percentage of people in the U.S. who use electricity to heat their homes. Past data indicate that 154 out of 700 customers surveyed used electricity to heat their homes. If the company wishes to be 98% confident to within 3%, how large a sample would be needed?
a. 516
b. 733
c. 854
d. 1036
e. 1266
f. 1503
g. 2066
h. none of these
Math QUestion?
The probability that k people in a sample of n people use electricity can be calculated using a binomial random variable..
P(K = k) = N-Choose-K p^k (1-p)^(n-k)
where p = 154/700 = .22
N-Choose-K = n! / [ (n-k)! * k!]
Let the lower limit be L1..
L1 = floor (.97 *.22 * n)
Let the upper limit be L2..
L2 = floor (1.03*.22*n)
Find the smallest n, such that
∑Pk ≥ .98
where the lower and upper limits to the summation are L1 and L2, respectively
When n=516, ∑Pk = .250
When n=733, ∑Pk = .344
When n=854, ∑Pk= .350
When n=1036, ∑Pk= .374
When n=1266, ∑Pk= .413
When n=1503, ∑Pk= .467
When n=2066, ∑Pk= .543
I calculated these in MathCad using this code:
N := 2066
L1 := floor(N*.22*.97)
L2 :=floor(N*.22*1.03)
pbinom(L2,N,.22) - pbinom(L1,N,.22) = .543
none of the answers came anywhere near .98.. however, when N=21091 =%26gt; .98 and when N=21090 =%26gt;.979
therefore N=21091
h) NONE OF THE ABOVE.
a. 516
b. 733
c. 854
d. 1036
e. 1266
f. 1503
g. 2066
h. none of these
Math QUestion?
The probability that k people in a sample of n people use electricity can be calculated using a binomial random variable..
P(K = k) = N-Choose-K p^k (1-p)^(n-k)
where p = 154/700 = .22
N-Choose-K = n! / [ (n-k)! * k!]
Let the lower limit be L1..
L1 = floor (.97 *.22 * n)
Let the upper limit be L2..
L2 = floor (1.03*.22*n)
Find the smallest n, such that
∑Pk ≥ .98
where the lower and upper limits to the summation are L1 and L2, respectively
When n=516, ∑Pk = .250
When n=733, ∑Pk = .344
When n=854, ∑Pk= .350
When n=1036, ∑Pk= .374
When n=1266, ∑Pk= .413
When n=1503, ∑Pk= .467
When n=2066, ∑Pk= .543
I calculated these in MathCad using this code:
N := 2066
L1 := floor(N*.22*.97)
L2 :=floor(N*.22*1.03)
pbinom(L2,N,.22) - pbinom(L1,N,.22) = .543
none of the answers came anywhere near .98.. however, when N=21091 =%26gt; .98 and when N=21090 =%26gt;.979
therefore N=21091
h) NONE OF THE ABOVE.
How can i email yahoo music unlimited directly?
someone give me an address or something where i can email yahoo unlimited directly, without filling out the stupid forms on the customer care site that don't even ask you what the problem is. this thing is expensive, and i want to talk to someone directly, not fill out a foolish survey. PLEASE HELP!!!
How can i email yahoo music unlimited directly?
If you want to cancel your subscription, you can do that here: http://help.yahoo.com/l/us/yahoo/music/j...
It doesn't seem like you can contact them directly. I don't know if this was the form you used to fill out, but this one seems to be accurate: http://help.yahoo.com/l/us/yahoo/music/b...
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How can i email yahoo music unlimited directly?
If you want to cancel your subscription, you can do that here: http://help.yahoo.com/l/us/yahoo/music/j...
It doesn't seem like you can contact them directly. I don't know if this was the form you used to fill out, but this one seems to be accurate: http://help.yahoo.com/l/us/yahoo/music/b...
used shoes
Statistics help Inference for Proportions?
An automobile manufacturer would like to know what proportion of its customers are dissatisfied with the service received from their local dealer. The customer relations department will survey a random sample of customers and compute a 95% confidence interval for the proportion that are dissatisfied. From past studies, they believe that this proportion will be about 0.23. Find the sample size needed if the margin of error of the confidence interval is to be about 0.01.
n =
After taking this survey with the sample size above, suppose 15% of the sample say that they are dissatisfied. What is the margin of error of the 95% confidence interval?
MOE =
If you had no prior information about possible values for p, how large a sample would be needed to be certain that the margin of error was at most 0.01 with 95% confidence?
n =
Statistics help Inference for Proportions?
large sample confidence intervals are used to find a region in which we are 100 (1-α)% confident the true value of the parameter is in the interval.
For large sample confidence intervals for the proportion in this situation you have:
pHat ± z * sqrt( (pHat * (1-pHat)) / n)
where pHat is the sample proportion
z is the zscore for having α% of the data in the tails, i.e., P( |Z| %26gt; z) = α
n is the sample size
-- -- -- -- -- -- -- --
in the first question we have to find the value of n for which
z * sqrt( (pHat * (1-pHat)) / n) %26lt; 0.01
the z-score for the 95% CI is z = 1.96
1.96 * sqrt( 0.23 * ( 1 - 0.23 ) / n ) %26lt; 0.01
sqrt(0.1771 / n ) %26lt; 0.005102041
0.1771 / n %26lt; 2.603082e-05
n %26gt; 0.1771 / 2.603082e-05
n %26gt; 6803.474
you need an integer value for n so n %26gt; 6804 for the margin or error to be 0.01 or smaller.
-- -- -- -- -- -- -- -- -- --
b)
1.96 * sqrt( 0.15 * (1 - 0.15) / 6804 ) = 0.008484554
-- -- -- -- -- -- -- -- -- --
c)
worse case is to have a proportion of 0.50. this maximizes the square root function. This is easy to prove in just a couple simple calculus steps.
1.96 * sqrt( 0.5 * 0.5 / n ) %26lt; 0.01
n %26gt; (0.5 * 0.5) / ((0.01 / 1.96) ^ 2)
n %26gt; 9604
n =
After taking this survey with the sample size above, suppose 15% of the sample say that they are dissatisfied. What is the margin of error of the 95% confidence interval?
MOE =
If you had no prior information about possible values for p, how large a sample would be needed to be certain that the margin of error was at most 0.01 with 95% confidence?
n =
Statistics help Inference for Proportions?
large sample confidence intervals are used to find a region in which we are 100 (1-α)% confident the true value of the parameter is in the interval.
For large sample confidence intervals for the proportion in this situation you have:
pHat ± z * sqrt( (pHat * (1-pHat)) / n)
where pHat is the sample proportion
z is the zscore for having α% of the data in the tails, i.e., P( |Z| %26gt; z) = α
n is the sample size
-- -- -- -- -- -- -- --
in the first question we have to find the value of n for which
z * sqrt( (pHat * (1-pHat)) / n) %26lt; 0.01
the z-score for the 95% CI is z = 1.96
1.96 * sqrt( 0.23 * ( 1 - 0.23 ) / n ) %26lt; 0.01
sqrt(0.1771 / n ) %26lt; 0.005102041
0.1771 / n %26lt; 2.603082e-05
n %26gt; 0.1771 / 2.603082e-05
n %26gt; 6803.474
you need an integer value for n so n %26gt; 6804 for the margin or error to be 0.01 or smaller.
-- -- -- -- -- -- -- -- -- --
b)
1.96 * sqrt( 0.15 * (1 - 0.15) / 6804 ) = 0.008484554
-- -- -- -- -- -- -- -- -- --
c)
worse case is to have a proportion of 0.50. this maximizes the square root function. This is easy to prove in just a couple simple calculus steps.
1.96 * sqrt( 0.5 * 0.5 / n ) %26lt; 0.01
n %26gt; (0.5 * 0.5) / ((0.01 / 1.96) ^ 2)
n %26gt; 9604
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